Integrand size = 18, antiderivative size = 251 \[ \int \frac {\sinh ^2(a+b x)}{(c+d x)^{9/2}} \, dx=-\frac {16 b^2}{105 d^3 (c+d x)^{3/2}}+\frac {32 b^{7/2} e^{-2 a+\frac {2 b c}{d}} \sqrt {2 \pi } \text {erf}\left (\frac {\sqrt {2} \sqrt {b} \sqrt {c+d x}}{\sqrt {d}}\right )}{105 d^{9/2}}+\frac {32 b^{7/2} e^{2 a-\frac {2 b c}{d}} \sqrt {2 \pi } \text {erfi}\left (\frac {\sqrt {2} \sqrt {b} \sqrt {c+d x}}{\sqrt {d}}\right )}{105 d^{9/2}}-\frac {8 b \cosh (a+b x) \sinh (a+b x)}{35 d^2 (c+d x)^{5/2}}-\frac {128 b^3 \cosh (a+b x) \sinh (a+b x)}{105 d^4 \sqrt {c+d x}}-\frac {2 \sinh ^2(a+b x)}{7 d (c+d x)^{7/2}}-\frac {32 b^2 \sinh ^2(a+b x)}{105 d^3 (c+d x)^{3/2}} \]
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Time = 0.30 (sec) , antiderivative size = 251, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.389, Rules used = {3395, 32, 3393, 3388, 2211, 2235, 2236} \[ \int \frac {\sinh ^2(a+b x)}{(c+d x)^{9/2}} \, dx=\frac {32 \sqrt {2 \pi } b^{7/2} e^{\frac {2 b c}{d}-2 a} \text {erf}\left (\frac {\sqrt {2} \sqrt {b} \sqrt {c+d x}}{\sqrt {d}}\right )}{105 d^{9/2}}+\frac {32 \sqrt {2 \pi } b^{7/2} e^{2 a-\frac {2 b c}{d}} \text {erfi}\left (\frac {\sqrt {2} \sqrt {b} \sqrt {c+d x}}{\sqrt {d}}\right )}{105 d^{9/2}}-\frac {128 b^3 \sinh (a+b x) \cosh (a+b x)}{105 d^4 \sqrt {c+d x}}-\frac {32 b^2 \sinh ^2(a+b x)}{105 d^3 (c+d x)^{3/2}}-\frac {8 b \sinh (a+b x) \cosh (a+b x)}{35 d^2 (c+d x)^{5/2}}-\frac {2 \sinh ^2(a+b x)}{7 d (c+d x)^{7/2}}-\frac {16 b^2}{105 d^3 (c+d x)^{3/2}} \]
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Rule 32
Rule 2211
Rule 2235
Rule 2236
Rule 3388
Rule 3393
Rule 3395
Rubi steps \begin{align*} \text {integral}& = -\frac {8 b \cosh (a+b x) \sinh (a+b x)}{35 d^2 (c+d x)^{5/2}}-\frac {2 \sinh ^2(a+b x)}{7 d (c+d x)^{7/2}}+\frac {\left (8 b^2\right ) \int \frac {1}{(c+d x)^{5/2}} \, dx}{35 d^2}+\frac {\left (16 b^2\right ) \int \frac {\sinh ^2(a+b x)}{(c+d x)^{5/2}} \, dx}{35 d^2} \\ & = -\frac {16 b^2}{105 d^3 (c+d x)^{3/2}}-\frac {8 b \cosh (a+b x) \sinh (a+b x)}{35 d^2 (c+d x)^{5/2}}-\frac {128 b^3 \cosh (a+b x) \sinh (a+b x)}{105 d^4 \sqrt {c+d x}}-\frac {2 \sinh ^2(a+b x)}{7 d (c+d x)^{7/2}}-\frac {32 b^2 \sinh ^2(a+b x)}{105 d^3 (c+d x)^{3/2}}+\frac {\left (128 b^4\right ) \int \frac {1}{\sqrt {c+d x}} \, dx}{105 d^4}+\frac {\left (256 b^4\right ) \int \frac {\sinh ^2(a+b x)}{\sqrt {c+d x}} \, dx}{105 d^4} \\ & = -\frac {16 b^2}{105 d^3 (c+d x)^{3/2}}+\frac {256 b^4 \sqrt {c+d x}}{105 d^5}-\frac {8 b \cosh (a+b x) \sinh (a+b x)}{35 d^2 (c+d x)^{5/2}}-\frac {128 b^3 \cosh (a+b x) \sinh (a+b x)}{105 d^4 \sqrt {c+d x}}-\frac {2 \sinh ^2(a+b x)}{7 d (c+d x)^{7/2}}-\frac {32 b^2 \sinh ^2(a+b x)}{105 d^3 (c+d x)^{3/2}}-\frac {\left (256 b^4\right ) \int \left (\frac {1}{2 \sqrt {c+d x}}-\frac {\cosh (2 a+2 b x)}{2 \sqrt {c+d x}}\right ) \, dx}{105 d^4} \\ & = -\frac {16 b^2}{105 d^3 (c+d x)^{3/2}}-\frac {8 b \cosh (a+b x) \sinh (a+b x)}{35 d^2 (c+d x)^{5/2}}-\frac {128 b^3 \cosh (a+b x) \sinh (a+b x)}{105 d^4 \sqrt {c+d x}}-\frac {2 \sinh ^2(a+b x)}{7 d (c+d x)^{7/2}}-\frac {32 b^2 \sinh ^2(a+b x)}{105 d^3 (c+d x)^{3/2}}+\frac {\left (128 b^4\right ) \int \frac {\cosh (2 a+2 b x)}{\sqrt {c+d x}} \, dx}{105 d^4} \\ & = -\frac {16 b^2}{105 d^3 (c+d x)^{3/2}}-\frac {8 b \cosh (a+b x) \sinh (a+b x)}{35 d^2 (c+d x)^{5/2}}-\frac {128 b^3 \cosh (a+b x) \sinh (a+b x)}{105 d^4 \sqrt {c+d x}}-\frac {2 \sinh ^2(a+b x)}{7 d (c+d x)^{7/2}}-\frac {32 b^2 \sinh ^2(a+b x)}{105 d^3 (c+d x)^{3/2}}+\frac {\left (64 b^4\right ) \int \frac {e^{-i (2 i a+2 i b x)}}{\sqrt {c+d x}} \, dx}{105 d^4}+\frac {\left (64 b^4\right ) \int \frac {e^{i (2 i a+2 i b x)}}{\sqrt {c+d x}} \, dx}{105 d^4} \\ & = -\frac {16 b^2}{105 d^3 (c+d x)^{3/2}}-\frac {8 b \cosh (a+b x) \sinh (a+b x)}{35 d^2 (c+d x)^{5/2}}-\frac {128 b^3 \cosh (a+b x) \sinh (a+b x)}{105 d^4 \sqrt {c+d x}}-\frac {2 \sinh ^2(a+b x)}{7 d (c+d x)^{7/2}}-\frac {32 b^2 \sinh ^2(a+b x)}{105 d^3 (c+d x)^{3/2}}+\frac {\left (128 b^4\right ) \text {Subst}\left (\int e^{i \left (2 i a-\frac {2 i b c}{d}\right )-\frac {2 b x^2}{d}} \, dx,x,\sqrt {c+d x}\right )}{105 d^5}+\frac {\left (128 b^4\right ) \text {Subst}\left (\int e^{-i \left (2 i a-\frac {2 i b c}{d}\right )+\frac {2 b x^2}{d}} \, dx,x,\sqrt {c+d x}\right )}{105 d^5} \\ & = -\frac {16 b^2}{105 d^3 (c+d x)^{3/2}}+\frac {32 b^{7/2} e^{-2 a+\frac {2 b c}{d}} \sqrt {2 \pi } \text {erf}\left (\frac {\sqrt {2} \sqrt {b} \sqrt {c+d x}}{\sqrt {d}}\right )}{105 d^{9/2}}+\frac {32 b^{7/2} e^{2 a-\frac {2 b c}{d}} \sqrt {2 \pi } \text {erfi}\left (\frac {\sqrt {2} \sqrt {b} \sqrt {c+d x}}{\sqrt {d}}\right )}{105 d^{9/2}}-\frac {8 b \cosh (a+b x) \sinh (a+b x)}{35 d^2 (c+d x)^{5/2}}-\frac {128 b^3 \cosh (a+b x) \sinh (a+b x)}{105 d^4 \sqrt {c+d x}}-\frac {2 \sinh ^2(a+b x)}{7 d (c+d x)^{7/2}}-\frac {32 b^2 \sinh ^2(a+b x)}{105 d^3 (c+d x)^{3/2}} \\ \end{align*}
Time = 0.36 (sec) , antiderivative size = 222, normalized size of antiderivative = 0.88 \[ \int \frac {\sinh ^2(a+b x)}{(c+d x)^{9/2}} \, dx=\frac {2 \left (-8 b^2 d (c+d x)^2+16 \sqrt {2} b^3 e^{2 a-\frac {2 b c}{d}} (c+d x)^3 \sqrt {-\frac {b (c+d x)}{d}} \Gamma \left (\frac {1}{2},-\frac {2 b (c+d x)}{d}\right )-16 \sqrt {2} b^3 e^{-2 a+\frac {2 b c}{d}} (c+d x)^3 \sqrt {\frac {b (c+d x)}{d}} \Gamma \left (\frac {1}{2},\frac {2 b (c+d x)}{d}\right )-15 d^3 \sinh ^2(a+b x)-16 b^2 d (c+d x)^2 \sinh ^2(a+b x)-6 b d^2 (c+d x) \sinh (2 (a+b x))-32 b^3 (c+d x)^3 \sinh (2 (a+b x))\right )}{105 d^4 (c+d x)^{7/2}} \]
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\[\int \frac {\sinh \left (b x +a \right )^{2}}{\left (d x +c \right )^{\frac {9}{2}}}d x\]
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Leaf count of result is larger than twice the leaf count of optimal. 1827 vs. \(2 (199) = 398\).
Time = 0.28 (sec) , antiderivative size = 1827, normalized size of antiderivative = 7.28 \[ \int \frac {\sinh ^2(a+b x)}{(c+d x)^{9/2}} \, dx=\text {Too large to display} \]
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Timed out. \[ \int \frac {\sinh ^2(a+b x)}{(c+d x)^{9/2}} \, dx=\text {Timed out} \]
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Time = 0.26 (sec) , antiderivative size = 118, normalized size of antiderivative = 0.47 \[ \int \frac {\sinh ^2(a+b x)}{(c+d x)^{9/2}} \, dx=-\frac {\frac {14 \, \sqrt {2} \left (\frac {{\left (d x + c\right )} b}{d}\right )^{\frac {7}{2}} e^{\left (\frac {2 \, {\left (b c - a d\right )}}{d}\right )} \Gamma \left (-\frac {7}{2}, \frac {2 \, {\left (d x + c\right )} b}{d}\right )}{{\left (d x + c\right )}^{\frac {7}{2}}} + \frac {14 \, \sqrt {2} \left (-\frac {{\left (d x + c\right )} b}{d}\right )^{\frac {7}{2}} e^{\left (-\frac {2 \, {\left (b c - a d\right )}}{d}\right )} \Gamma \left (-\frac {7}{2}, -\frac {2 \, {\left (d x + c\right )} b}{d}\right )}{{\left (d x + c\right )}^{\frac {7}{2}}} - \frac {1}{{\left (d x + c\right )}^{\frac {7}{2}}}}{7 \, d} \]
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\[ \int \frac {\sinh ^2(a+b x)}{(c+d x)^{9/2}} \, dx=\int { \frac {\sinh \left (b x + a\right )^{2}}{{\left (d x + c\right )}^{\frac {9}{2}}} \,d x } \]
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Timed out. \[ \int \frac {\sinh ^2(a+b x)}{(c+d x)^{9/2}} \, dx=\int \frac {{\mathrm {sinh}\left (a+b\,x\right )}^2}{{\left (c+d\,x\right )}^{9/2}} \,d x \]
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